This article describe the t-test effect size. The most commonly used measure of effect size for a t-test is the Cohen’s d (Cohen 1998).
The d
statistic redefines the difference in means as the number of standard deviations that separates those means. The formula looks like this (Navarro 2015):
\[
d = \frac{\mbox{(mean 1)} - \mbox{(mean 2)}}{\mbox{std dev}}
\]
In this article, you will learn:
- Cohen’s d formula to calculate the effect size for one-sample t-test, for independent t-test (with pooled standard deviation or not) and for paired samples t-test (also known as repeated measures t-test).
- Effect size interpretation describing the critical value corresponding to small, medium and large effect sizes.
- Calculation of the Cohen’s d in R
Contents:
Related Book
Practical Statistics in R II - Comparing Groups: Numerical VariablesPrerequisites
Load the required R package for computing the Cohen’s d:
library(rstatix)
Demo dataset:
head(ToothGrowth, 3)
## len supp dose
## 1 4.2 VC 0.5
## 2 11.5 VC 0.5
## 3 7.3 VC 0.5
Effect size interpretation
T-test conventional effect sizes, poposed by Cohen, are: 0.2 (small efect), 0.5 (moderate effect) and 0.8 (large effect) (Cohen 1998, Navarro (2015)). This means that if two groups’ means don’t differ by 0.2 standard deviations or more, the difference is trivial, even if it is statistically significant.
d-value | rough interpretation |
---|---|
0.2 | Small effect |
0.5 | Moderate effect |
0.8 | Large effect |
Cohen’s d for one-sample t-test
To calculate an effect size, called Cohen's d
, for the one-sample t-test you need to divide the mean difference by the standard deviation of the difference, as shown below. Note that, here: sd(x-mu) = sd(x)
.
Cohen’s d formula:
\[
d = \frac{m-\mu}{s}
\]
- \(m\) is the sample mean
- \(s\) is the sample standard deviation with \(n-1\) degrees of freedom
- \(\mu\) is the theoretical mean against which the mean of our sample is compared (default value is mu = 0).
Calculation:
ToothGrowth %>% cohens_d(len ~ 1, mu = 0)
## # A tibble: 1 x 6
## .y. group1 group2 effsize n magnitude
## * <chr> <chr> <chr> <dbl> <int> <ord>
## 1 len 1 null model 2.46 60 large
Cohen’s d for independent t-test
The independent samples t-test comes in two different forms:
- the standard Student’s t-test, which assumes that the variance of the two groups are equal.
- the Welch’s t-test, which is less restrictive compared to the original Student’s test. This is the test where you do not assume that the variance is the same in the two groups, which results in the fractional degrees of freedom.
Cohen’s d for Student t-test
There are multiple version of Cohen’s d for Student t-test. The most commonly used version of the Student t-test effect size, comparing two groups (\(A\) and \(B\)), is calculated by dividing the mean difference between the groups by the pooled standard deviation.
Cohen’s d formula:
\[
d = \frac{m_A - m_B}{SD_{pooled}}
\]
where,
- \(m_A\) and \(m_B\) represent the mean value of the group A and B, respectively.
- \(n_A\) and \(n_B\) represent the sizes of the group A and B, respectively.
- \(SD_{pooled}\) is an estimator of the pooled standard deviation of the two groups. It can be calculated as follow :
\[
SD_{pooled} = \sqrt{\frac{\sum{(x-m_A)^2}+\sum{(x-m_B)^2}}{n_A+n_B-2}}
\]
Calculation. If the option var.equal = TRUE
, then the pooled SD is used when compting the Cohen’s d.
ToothGrowth %>% cohens_d(len ~ supp, var.equal = TRUE)
## # A tibble: 1 x 7
## .y. group1 group2 effsize n1 n2 magnitude
## * <chr> <chr> <chr> <dbl> <int> <int> <ord>
## 1 len OJ VC 0.495 30 30 small
Note that, for small sample size (< 50), the Cohen’s d tends to over-inflate results. There exists a Hedge’s Corrected version of the Cohen’s d (Hedges and Olkin 1985), which reduces effect sizes for small samples by a few percentage points. The correction is introduced by multiplying the usual value of d by (N-3)/(N-2.25)
(for unpaired t-test) and by (n1-2)/(n1-1.25)
for paired t-test; where N is the total size of the two groups being compared (N = n1 + n2)
.
ToothGrowth %>% cohens_d(
len ~ supp, var.equal = TRUE,
hedges.correction = TRUE
)
## # A tibble: 1 x 7
## .y. group1 group2 effsize n1 n2 magnitude
## * <chr> <chr> <chr> <dbl> <int> <int> <ord>
## 1 len OJ VC 0.488 30 30 small
Cohen’s d for Welch test
The Welch test is a variant of t-test used when the equality of variance can’t be assumed. The effect size can be computed by dividing the mean difference between the groups by the “averaged” standard deviation.
Cohen’s d formula:
\[
d = \frac{m_A - m_B}{\sqrt{(Var_1 + Var_2)/2}}
\]
where,
- \(m_A\) and \(m_B\) represent the mean value of the group A and B, respectively.
- \(Var_1\) and \(Var_2\) are the variance of the two groups.
Calculation:
ToothGrowth %>% cohens_d(len ~ supp, var.equal = FALSE)
## # A tibble: 1 x 7
## .y. group1 group2 effsize n1 n2 magnitude
## * <chr> <chr> <chr> <dbl> <int> <int> <ord>
## 1 len OJ VC 0.495 30 30 small
Cohen’s d for paired samples t-test
The effect size for a paired-samples t-test can be calculated by dividing the mean difference by the standard deviation of the difference, as shown below.
Cohen’s d formula:
\[
d = \frac{mean_D}{SD_D}
\]
Where D
is the differences of the paired samples values.
Calculation:
ToothGrowth %>% cohens_d(len ~ supp, paired = TRUE)
## # A tibble: 1 x 7
## .y. group1 group2 effsize n1 n2 magnitude
## * <chr> <chr> <chr> <dbl> <int> <int> <ord>
## 1 len OJ VC 0.603 30 30 moderate
Summary
This article shows how to compute and interpret the t-test effect using the Cohen’s d statistic. We describe the formula of the Cohen’s d for one-sample, two-samples and paired samples t-test. Examples of R codes are provided for the calculations.
References
Cohen, J. 1998. Statistical Power Analysis for the Behavioral Sciences. 2nd ed. Hillsdale, NJ: Lawrence Erlbaum Associates.
Hedges, Larry, and Ingram Olkin. 1985. “Statistical Methods in Meta-Analysis.” In Stat Med. Vol. 20. doi:10.2307/1164953.
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Dividing the mean difference by the standard deviation of the differences does not conform with the definition of Cohen’s d. With this computation, if each person in the sample would increase or decrease with the exact same amount (however small or large), then this would yield an effect size of (minus) infinity. The proposed ‘effect size’ says something about the variability of the effect, but nothing about the strength of the effect. To obtain an actual effect size, one should divide the mean difference by the pooled pre- or post-test standard deviation.