The independent samples t-test comes in two different forms:
- the standard Student’s t-test, which assumes that the variance of the two groups are equal.
- the Welch’s t-test, which is less restrictive compared to the original Student’s test. This is the test where you do not assume that the variance is the same in the two groups, which results in the fractional degrees of freedom.
Note that, the Welch t-test is considered as the safer one. Usually, the results of the classical student’s t-test and the Welch t-test are very similar unless both the group sizes and the standard deviations are very different.
This article describes the Welch t-test, which is an adaptation of the Student’s t-test for comparing the means of two independent groups, in the situation where the homogeneity of variance assumption is not met. The Welch t-test is also referred as: Welch’s t-test, Welchs t-test, t-test unequal variance, t-test assuming unequal variances or separate variance t-test
In this article, you will learn:
- Welch t-test formula and assumptions
- How to compute, interpret and report the Welch t-test in R.
- How to check the Welch t-test assumptions
Contents:
Related Book
Practical Statistics in R II - Comparing Groups: Numerical VariablesPrerequisites
Make sure you have installed the following R packages:
tidyverse
for data manipulation and visualizationggpubr
for creating easily publication ready plotsrstatix
provides pipe-friendly R functions for easy statistical analyses.datarium
: contains required data sets for this chapter.
Start by loading the following required packages:
library(tidyverse)
library(ggpubr)
library(rstatix)
Research questions
A typical research questions is: whether the mean of group A (\(m_A\)) is equal to the mean of group B (\(m_B\))?
Statistical hypotheses
- Null hypothesis (Ho): the two group means are identical (\(m_A = m_B\))
- Alternative hypothesis (Ha): the two group means are different (\(m_A \ne m_B\))
Formula
The Welch t-statistic is calculated as follow :
\[
t = \frac{m_A - m_B}{\sqrt{ \frac{S_A^2}{n_A} + \frac{S_B^2}{n_B} }}
\]
where, \(S_A\) and \(S_B\) are the standard deviation of the the two groups A and B, respectively.
Unlike the classic Student’s t-test, the Welch t-test formula involves the variance of each of the two groups (\(S_A^2\) and \(S_B^2\)) being compared. In other words, it does not use the pooled variance\(S\).
The degrees of freedom of Welch t-test is estimated as follow :
\[
df = (\frac{S_A^2}{n_A}+ \frac{S_B^2}{n_B})^2 / (\frac{S_A^4}{n_A^2(n_A-1)} + \frac{S_B^4}{n_B^2(n_B-1)} )
\]
A p-value can be computed for the corresponding absolute value of t-statistic (|t|).
If the p-value is inferior or equal to the significance level 0.05, we can reject the null hypothesis and accept the alternative hypothesis. In other words, we can conclude that the mean values of group A and B are significantly different.
Assumptions and preleminary tests
The Welch t-test assumes the following characteristics about the data:
- Independence of the observations. Each subject should belong to only one group.
- No significant outliers in the two groups
- Normality. the data for each group should be approximately normally distributed.
Click to check the Student t-test assumptions.
Calculating the test in R
Demo data
Demo dataset: genderweight
[in datarium package] containing the weight of 40 individuals (20 women and 20 men).
Load the data and show some random rows by groups:
# Load the data
data("genderweight", package = "datarium")
# Show a sample of the data by group
set.seed(123)
genderweight %>% sample_n_by(group, size = 2)
## # A tibble: 4 x 3
## id group weight
## <fct> <fct> <dbl>
## 1 6 F 65.0
## 2 15 F 65.9
## 3 29 M 88.9
## 4 37 M 77.0
Summary statistics
Compute some summary statistics by groups: mean and sd (standard deviation)
genderweight %>%
group_by(group) %>%
get_summary_stats(weight, type = "mean_sd")
## # A tibble: 2 x 5
## group variable n mean sd
## <fct> <chr> <dbl> <dbl> <dbl>
## 1 F weight 20 63.5 2.03
## 2 M weight 20 85.8 4.35
Visualization
Visualize the data using box plots. Plot weight by groups.
bxp <- ggboxplot(
genderweight, x = "group", y = "weight",
ylab = "Weight", xlab = "Groups", add = "jitter"
)
bxp
Computation
We’ll use the pipe-friendly t_test()
function [rstatix package], a wrapper around the R base function t.test()
.
Recall that, by default, R computes the Welch t-test, which is the safer one. This is the test where you do not assume that the variance is the same in the two groups, which results in the fractional degrees of freedom. If you want to assume the equality of variances (Student t-test), specify the option var.equal = TRUE
.
stat.test <- genderweight %>%
t_test(weight ~ group) %>%
add_significance()
stat.test
## # A tibble: 1 x 9
## .y. group1 group2 n1 n2 statistic df p p.signif
## <chr> <chr> <chr> <int> <int> <dbl> <dbl> <dbl> <chr>
## 1 weight F M 20 20 -20.8 26.9 4.30e-18 ****
The results above show the following components:
.y.
: the y variable used in the test.group1,group2
: the compared groups in the pairwise tests.statistic
: Test statistic used to compute the p-value.df
: degrees of freedom.p
: p-value.
Note that, you can obtain a detailed result by specifying the option detailed = TRUE
.
Cohen’s d for Welch t-test
The effect size can be computed by dividing the mean difference between the groups by the “averaged” standard deviation.
Cohen’s d formula:
d = (mean1 - mean2)/sqrt((var1 + var2)/2)
, where:
mean1
andmean2
are the means of each group, respectivelyvar1
andvar2
are the variance of the two groups.
Calculation:
genderweight %>% cohens_d(weight ~ group, var.equal = FALSE)
## # A tibble: 1 x 7
## .y. group1 group2 effsize n1 n2 magnitude
## * <chr> <chr> <chr> <dbl> <int> <int> <ord>
## 1 weight F M -6.57 20 20 large
Report
We could report the result as follow:
The mean weight in female group was 63.5 (SD = 2.03), whereas the mean in male group was 85.8 (SD = 4.3). A Welch two-samples t-test showed that the difference was statistically significant, t(26.9) = -20.8, p < 0.0001, d = 6.57; where, t(26.9) is shorthand notation for a Welch t-statistic that has 26.9 degrees of freedom.
stat.test <- stat.test %>% add_xy_position(x = "group")
bxp +
stat_pvalue_manual(stat.test, tip.length = 0) +
labs(subtitle = get_test_label(stat.test, detailed = TRUE))
Summary
This article describes the formula and the basics of the Welch t-test. Examples of R codes are provided for computing the test and the effect size, interpreting and reporting the results.
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Example:
s1 = 2, s2 = 2
n1 = 4, n2 = 6
In this case df = 6,57.
If sample 2 is measured more often (e.g. n=7) then df decreases again. Why is that?
What is the mathematical formula (not the software commands) used to convert the test statistic and the degrees of freedom to a p-value?